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Randomized query complexity can beat certificate complexity

▲ 5 points • 0 comments • by porridgeraisin • 3w ago • HN discussion ↗

Pangram verdict · v3.3

We believe that this entire text is human-written.

0 %

AI likelihood · overall

Human
100% human-written 0% AI-generated
SEGMENTS · HUMAN 1 of 1
SEGMENTS · AI 0 of 1
WORD COUNT 117
PEAK AI % 0% · §1
Analyzed
Sep 16
backend: pangram/v3.3
Segments scanned
1 windows
avg 117 words each
Distribution
100 / 0%
human / AI fraction
Verdict
Human
Pangram v3.3

Article text · 117 words · 1 segments analyzed

Human AI-generated
§1 Human · 0%

View PDF HTML (experimental) Abstract:A long-standing open question in query complexity asks whether there is a total Boolean function f with R(f) << C(f), where R(f) and C(f) denote its bounded-error randomized query complexity and certificate complexity, respectively. We construct a function with R(f) = O~(sqrt{C(f)}), which is optimal up to log factors. The same function also has $Q(f) = O~(C(f)^{1/4}), where Q(f) is the bounded-error quantum query complexity of f, which is also nearly optimal. Comments: 6 pages Subjects: Computational Complexity (cs.CC); Quantum Physics (quant-ph) Cite as: arXiv:2609.15063 [cs.CC] (or arXiv:2609.15063v1 [cs.CC] for this version) https://doi.org/10.48550/arXiv.2609.15063 arXiv-issued DOI via DataCite Submission history From: Robin Kothari [view email] [v1] Mon, 14 Sep 2026 05:29:42 UTC (9 KB)